Question - Given a list of ints, return True if the array contains a 3 next to a 3 somewhere.
has_33([1, 3, 3]) → True
has_33([1, 3, 1, 3]) → False
has_33([3, 1, 3]) → False
Why can I not solve this problem with a while loop instead of the said method ? If I can, please tell me how do I get it to wo...